Practice problem
Solve the equation log2(x)+log2(x+3)=2\log_2(x) + \log_2(x + 3) = 2log2(x)+log2(x+3)=2.
x=1x = 1x=1
x=−4x = -4x=−4
x=1x = 1x=1 and x=−4x = -4x=−4
No real solutions
Type a concept, like “slope” or “photosynthesis”.
