We want to compute some binomial coefficients knowing the values

(50)=1{{5}\choose{0}} = 1 (51)=5{{5}\choose{1}} = 5 (52)=10{{5}\choose{2}} = 10 (53)=10{{5}\choose{3}} = 10 (54)=5{{5}\choose{4}} = 5 (55)=1{{5}\choose{5}} = 1

If we want to evaluate (94){{9}\choose{4}} by repeatedly using Pascal's Identity until the expression is only in terms of the six binomial coefficient evaluations above, what is the smallest number of times must we use Pascal's Identity?

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