Practice problem
Convert −5i-5i−5i to polar form.
−5(cos(π2)+isin(π2))-5(\text{cos}(\frac{\pi}{2})+ i\text{sin}(\frac{\pi}{2}))−5(cos(2π)+isin(2π))
−5(cos(3π2)+isin(3π2))-5(\text{cos}(\frac{3\pi}{2})+ i\text{sin}(\frac{3\pi}{2}))−5(cos(23π)+isin(23π))
5(cos(3π2)+isin(3π2))5(\text{cos}(\frac{3\pi}{2})+ i\text{sin}(\frac{3\pi}{2}))5(cos(23π)+isin(23π))
Not possible
Type a concept, like “slope” or “photosynthesis”.
