Practice problem
Let z=4+2i5.z=4+2i\sqrt{5}.z=4+2i5.
Convert c=6−−zzˉc=6-\sqrt{-z\bar{z}}c=6−−zzˉ to polar form.
72(cos(5π4)+isin(5π4))\sqrt{72}(\text{cos}(\frac{5\pi}{4})+i\text{sin}(\frac{5\pi}{4}))72(cos(45π)+isin(45π))
6(cos(7π4)+isin(7π4))6(\text{cos}(\frac{7\pi}{4})+i\text{sin}(\frac{7\pi}{4}))6(cos(47π)+isin(47π))
62(cos(−π4)+isin(−π4))6\sqrt{2}(\text{cos}(\frac{-\pi}{4})+i\text{sin}(\frac{-\pi}{4}))62(cos(4−π)+isin(4−π))
62(cos(3π4)+isin(3π4))6\sqrt{2}(\text{cos}(\frac{3\pi}{4})+i\text{sin}(\frac{3\pi}{4}))62(cos(43π)+isin(43π))
Type a concept, like “slope” or “photosynthesis”.
