Practice problem
If f(x)=x2+x+1xf(x)= \dfrac{x^2+x+1}{x}f(x)=xx2+x+1, find f−1(x)f^{-1}(x)f−1(x).
f−1(x)=1+x+x2−2x−32f^{-1}(x)= \dfrac{ 1+x+\sqrt{ x^2-2x-3}}{2}f−1(x)=21+x+x2−2x−3
f−1(x)=1−x+x2−2x−32or 1+x−x2−2x−32f^{-1}(x)= \dfrac{ 1-x+\sqrt{ x^2-2x-3}}{2} \text{or } \dfrac{ 1+x-\sqrt{ x^2-2x-3}}{2}f−1(x)=21−x+x2−2x−3or 21+x−x2−2x−3
f−1(x)=−1+x+x2−2x−32or −1+x−x2−2x−32f^{-1}(x)= \dfrac{ -1+x+\sqrt{ x^2-2x-3}}{2} \text{or } \dfrac{ -1+x-\sqrt{ x^2-2x-3}}{2}f−1(x)=2−1+x+x2−2x−3or 2−1+x−x2−2x−3
f−1(x)=1−x+x2−2x−33or 1+x−x2−3x−32f^{-1}(x)= \dfrac{ 1-x+\sqrt{ x^2-2x-3}}{3} \text{or } \dfrac{ 1+x-\sqrt{ x^2-3x-3}}{2}f−1(x)=31−x+x2−2x−3or 21+x−x2−3x−3
Type a concept, like “slope” or “photosynthesis”.
