Practice problem
Find the inverse of f(x)=x3−7f(x)= x^3-7f(x)=x3−7
f−1(x)=x+73f^{-1}(x)= \sqrt[3]{x +7}f−1(x)=3x+7
f−1(x)=x+37f^{-1}(x)= \sqrt[7]{x +3}f−1(x)=7x+3
f−1(x)=13x+7f^{-1}(x)= \dfrac{1}{3} x +7f−1(x)=31x+7
f−1(x)=x+7f^{-1}(x)= \sqrt{x +7}f−1(x)=x+7
Type a concept, like “slope” or “photosynthesis”.
