Practice problem
Find the inverse of the function f(x)=1x2f(x)=\dfrac {1}{x^2}f(x)=x21
f−1(x)=x or −xf^{-1}(x)= \sqrt{x} \text { or } - \sqrt{x}f−1(x)=x or −x
f−1(x)=x4 or −x4f^{-1}(x)= \dfrac{\sqrt{x}}{4} \text { or } - \dfrac{\sqrt{x}}{4}f−1(x)=4x or −4x
f−1(x)=1x or −1xf^{-1}(x)= \sqrt{\dfrac {1}{x}} \text { or } - \sqrt{\dfrac {1}{x}}f−1(x)=x1 or −x1
f−1(x)=x2 or −x2f^{-1}(x)= \sqrt{\dfrac{x}{2}} \text { or } - \sqrt{\dfrac{x}{2}}f−1(x)=2x or −2x
Type a concept, like “slope” or “photosynthesis”.
