Practice problem
Find the inverse of f(x)=3x3+9f(x)= 3x^3+9f(x)=3x3+9
f−1(x)=x−933f^{-1}(x) = \sqrt[3]{\dfrac{x-9}{3}}f−1(x)=33x−9
f−1(x)=x−93f^{-1}(x) = \sqrt[3]{x-9}f−1(x)=3x−9
f−1(x)=x−333f^{-1}(x) = \sqrt[3]{\dfrac{x-3}{3}}f−1(x)=33x−3
f−1(x)=x−993f^{-1}(x) = \sqrt[3]{\dfrac{x-9}{9}}f−1(x)=39x−9
Type a concept, like “slope” or “photosynthesis”.
