Practice problem

Piecewise Linear Functions

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Contributors

Amy Feraco
Victor Wang

Given the function below, which of the following table of values is correct? $f(x)=\begin{cases} 2&0\le {x}\le{2}\\ -x+3&2<x\le{4}\\ -2&4<x\le{6}\\ x-7&6<x\le{9}\\ \frac{3}{2}x-16&9<x\le{13} \end{cases}$

Choose one answer

\begin{array}{|r|c|c|c|c|c|c|c|c|} \hline \text{Input:}&1&2&3&4&6&8&9&12\\ \hline \text{Output:}&2&1&0&-2&-1&1&2&2\\ \hline \end{array}

\begin{array}{|r|c|c|c|c|c|c|c|c|} \hline \text{Input:}&-1&2&3&4&6&-8&9&12\\ \hline \text{Output:}&2&2&0&-1&-2&1&2&2\\ \hline \end{array}

\begin{array}{|r|c|c|c|c|c|c|c|c|} \hline \text{Input:}&1&2&3&4&6&8&9&12\\ \hline \text{Output:}&2&-2&2&-1&-2&1&2&2\\ \hline \end{array}

\begin{array}{|r|c|c|c|c|c|c|c|c|} \hline \text{Input:}&1&2&3&4&6&8&9&12\\ \hline \text{Output:}&2&2&0&-1&-2&1&2&2\\ \hline \end{array}