Practice problem
In the following function, where are the points of discontinuity? f(x)=x+3x3+3x2−x−3f(x)=\frac{x+3}{x^3+3x^2-x-3}f(x)=x3+3x2−x−3x+3
Asymptote at y=0y=0y=0
Asymptote at x=−1x=-1x=−1
Asymptote at x=1x=1x=1
Hole at x=−1x=-1x=−1
Hole at x=−3x=-3x=−3
Type a concept, like “slope” or “photosynthesis”.