Practice problem
Where are the points of discontinuity in the following function? f(x)=(x2−x−12)(x2−5x+4)f(x)=\frac{(x^{2}-x-12)}{(x^{2}-5x+4)}f(x)=(x2−5x+4)(x2−x−12)
Vertical asymptote as x=1x=1x=1.
Hole at x=4x=4x=4.
Vertical asymptote as x=−1x=-1x=−1.
Hole at x=−4x=-4x=−4.
Type a concept, like “slope” or “photosynthesis”.