Practice problem
Which line is perpendicular to y=57xy=\frac{5}{7}xy=75x?
y=75xy=\frac{7}{5}xy=57x
y=−57x+4y=\frac{-5}{7} x+4y=7−5x+4
y=−75x+7y=\frac{-7}{5} x+7y=5−7x+7
y=12xy=12xy=12x
Type a concept, like “slope” or “photosynthesis”.
