Practice problem
What is the inverse of the function f(x)=1x2f(x)=\frac{1}{x^{2}}f(x)=x21, and what is its domain?
f−1(x)=1x2f^{-1}(x) = \frac{1}{x^2}f−1(x)=x21 with domain (0,∞)(0,\infty)(0,∞)
f−1(x)=1x2f^{-1}(x) = \frac{1}{x^2}f−1(x)=x21 with domain [0,∞)[0,\infty)[0,∞)
f−1(x)=1xf^{-1}(x) = \frac{1}{\sqrt{x}}f−1(x)=x1 with domain [0,∞)[0,\infty)[0,∞)
f−1(x)=1xf^{-1}(x) = \frac{1}{\sqrt{x}}f−1(x)=x1 with domain (0,∞)(0,\infty)(0,∞)
Type a concept, like “slope” or “photosynthesis”.