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Practice problem

Domain of Inverse Function

By Amy Feraco
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The inverse of f(x)=sin⁡(x)f(x)=\sin{(x)} is f−1(x)=arcsin⁡(x)f^{-1}(x)=\arcsin{(x)} or f−1(x)=sin⁡−1(x)f^{-1}(x)=\sin^{-1}{(x)}.

What is the domain of the inverse if the domain of f(x)=sin⁡(x)f(x)=\sin{(x)} is [−π2,π2][-\frac{\pi}{2},{\frac{\pi}{2}}] and the range is [−1,1][-1,{1}]?

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