Practice problem
What is the inverse of the following function? f(x)=5(x−3)5+19f(x)=5(x-3)^5+19f(x)=5(x−3)5+19
f−1(x)=(x−193)5+3f^{-1}(x)=\left(\frac{x-19}{3}\right)^{5}+3f−1(x)=(3x−19)5+3
f−1(x)=x−1955+3f^{-1}(x)=\sqrt[5]{\frac{x-19}{5}}+3f−1(x)=55x−19+3
f−1(x)=x−1953+3f^{-1}(x)=\sqrt[3]{\frac{x-19}{5}}+3f−1(x)=35x−19+3
Type a concept, like “slope” or “photosynthesis”.