Practice problem
What is the inverse of the function f(x)=(x−2)8+12?f(x)= (x-2)^8+\frac{1}{2}?f(x)=(x−2)8+21?
f−1(x)=(x−12)18+2f^{-1}(x)= \left(x-\frac{1}{2}\right)^{\frac{1}{8}}+2f−1(x)=(x−21)81+2
f−1(x)=(x−12)14+2f^{-1}(x)= \left(x-\frac{1}{2}\right)^{\frac{1}{4}}+2f−1(x)=(x−21)41+2
f−1(x)=(x−12)+2f^{-1}(x)= \sqrt{\left(x-\frac{1}{2}\right)}+2f−1(x)=(x−21)+2 when the domain of f(x)f(x)f(x) is x>2x>2x>2.
f−1(x)=(x−12)18+2f^{-1}(x)= \left(x-\frac{1}{2}\right)^{\frac{1}{8}}+2f−1(x)=(x−21)81+2 when the domain of f(x)f(x)f(x) is x>2x>2x>2.
Type a concept, like “slope” or “photosynthesis”.
