Practice problem
Given g(x)g(x)g(x) is a leftward shift of 222 from f(x)=1xf(x)=\frac{1}{x}f(x)=x1, what is the equation of g(x)g(x)g(x)?
g(x)=1x+2g(x)=\frac{1}{x+2}g(x)=x+21
g(x)=1x−2g(x)=\frac{1}{x-2}g(x)=x−21
g(x)=1x+2g(x)=\frac{1}{x}+2g(x)=x1+2
g(x)=1x−2g(x)=\frac{1}{x}-2g(x)=x1−2
Type a concept, like “slope” or “photosynthesis”.