Practice problem
Find all solutions to the following system: {x2−4x+8=y2+42x+4y=y2−12\begin{cases}x^2-4x+8=y^2+4\\2x+4y=y^2-12 \end{cases}{x2−4x+8=y2+42x+4y=y2−12
(0,−2)(0,-2)(0,−2)
(2,0)(2,0)(2,0)
(1+17,1−17)(1+\sqrt{17},1-\sqrt{17})(1+17,1−17)
(10,8)(10,8)(10,8)
(8,10)(8,10)(8,10)
(1−17,1+17)(1-\sqrt{17},1+\sqrt{17})(1−17,1+17)
Type a concept, like “slope” or “photosynthesis”.
