There is a unique twice-differentiable function gg on the positive reals such that g(x)+2x3g′(x)+x4g′′(x)=0g(x) + 2x^3 g'(x) + x^4 g''(x) = 0 for all positive reals xx, and lim⁡x→∞xg(x)=1\lim_{x\to\infty} xg(x) = 1. There is a unique real number a>1a > 1 such that g(a)=1/2g(a) = 1/2. Find π⋅a\pi \cdot a.

Source: HMMT February 2007

Hint: For intuition, write g(x)=∑n=−∞∞cnxng(x) = \sum_{n=-\infty}^{\infty} c_n x^n (temporarily ignoring convergence issues). Then the differential equation for gg gives you a linear recurrence; what are the solutions of this linear recurrence?

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