Practice problem
The sequence (xn)n≥1(x_n)_{n\ge1}(xn)n≥1 of reals satisfies limn→∞(x2n+x2n+1)=315\lim_{n\to\infty} (x_{2n} + x_{2n+1}) = 315limn→∞(x2n+x2n+1)=315 and limn→∞(x2n+x2n−1)=2003\lim_{n\to\infty}(x_{2n} + x_{2n-1}) = 2003limn→∞(x2n+x2n−1)=2003. Find limn→∞x2n/x2n+1\lim_{n\to\infty} x_{2n}/x_{2n+1}limn→∞x2n/x2n+1.
Source: HMMT February 2003
-1
0
1
2
Type a concept, like “slope” or “photosynthesis”.
