Practice problem
Let L=limn→∞∑i=0n−1(n2−i2)−1/2L = \lim_{n\to\infty} \sum_{i=0}^{n-1} (n^2 - i^2)^{-1/2}L=limn→∞∑i=0n−1(n2−i2)−1/2. Find π/L\pi/Lπ/L.
Source: HMMT February 2003
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Type a concept, like “slope” or “photosynthesis”.
