In triangle ABCABC, FF is on segment ABAB such that CFCF bisects ∠ACB\angle ACB. Points DD and EE are on line CFCF such that lines AD,BEAD,BE are perpendicular to CFCF. MM is the midpoint of ABAB. If ME=13ME=13, AD=15AD=15, and BE=25BE=25, find AC+CBAC+CB.

Source: 2012-2013 Winter Online Math Open

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