Christian wants to put x(1x+2x−1)=6x(\frac{1}{x}+2x-1)=6 into standard quadratic form: ax2+bx+c=0,a≠0ax^2 + bx + c = 0, a\neq 0 (Here x≠0x\ne 0.)

What constant term cc does he get in the end?

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