Practice problem
Solve for LLL. T=2πLgT=2\pi\sqrt{\frac{L}{g}}T=2πgL
L=(T2π)2gL=(\frac{T}{2\pi})^2gL=(2πT)2g
L=(Tg2π)2L=(\frac{Tg}{2\pi})^2L=(2πTg)2
L=Tg2πL=\frac{T\sqrt{g}}{2\pi}L=2πTg
L=g4π T2L=\frac{g}{4\pi}\ T^2L=4πg T2
Type a concept, like “slope” or “photosynthesis”.