Practice problem
Solve for the radius of a sphere, rrr, in terms of the volume, VVV. V=43 πr3V=\frac{4}{3}\ \pi r^3V=34 πr3
r=3V4π3r=\sqrt[3]{\frac{3V}{4\pi}}r=34π3V
r=3V4πr=\sqrt{\frac{3V}{4\pi}}r=4π3V
r=−3V4π3r=-\sqrt[3]{\frac{3V}{4\pi}}r=−34π3V
r=4V3π3r=\sqrt[3]{\frac{4V}{3\pi}}r=33π4V
Type a concept, like “slope” or “photosynthesis”.