Practice problem
The surface area of a cone can be found using the following equation. SA=πrr2+h2S_A=\pi r\sqrt{r^2+h^2}SA=πrr2+h2 Solve for hhh.
h=SA2−π2r4πrh=\frac{\sqrt{S_A^2-\pi^2r^4}}{\pi r}h=πrSA2−π2r4
h=SA−πr2πrh=\frac{S_A-\pi r^2}{\pi r}h=πrSA−πr2
h=SA2−π2r4πrh=\sqrt{\frac{S_A^2-\pi^2r^4}{\pi r}}h=πrSA2−π2r4
h=SA2−π2r4πSAh=\frac{\sqrt{S_A^2-\pi^2r^4}}{\pi S_A}h=πSASA2−π2r4
Type a concept, like “slope” or “photosynthesis”.