Practice problem
Find the the solution(s) to the following system by substitution. {x=y+2y=−1\left\{\begin{matrix}x=\sqrt{y+2}\\y=-1\end{matrix}\right.{x=y+2y=−1
(3,−1)(\sqrt{3},-1)(3,−1)
(1,1)(1,1)(1,1)
(1,−1)(1,-1)(1,−1)
(−2,−1)(-2,-1)(−2,−1)
(0,0)(0,0)(0,0)
Type a concept, like “slope” or “photosynthesis”.
