Practice problem
Find the discriminant of y(x)=12x2+6x+21y(x)=\frac{1}{2}x^2+6x+21y(x)=21x2+6x+21, and call it Δ.\Delta.Δ. How many real solutions does y(x)=0y(x) = 0y(x)=0 have?
Δ=−6\Delta=-6Δ=−6
Δ=6\Delta=6Δ=6
Δ=3\Delta=3Δ=3
Δ=−3\Delta=-3Δ=−3
Δ=1\Delta=1Δ=1
Δ=−1\Delta=-1Δ=−1
Δ=0\Delta=0Δ=0
000 solutions
111 solution
222 solutions
Type a concept, like “slope” or “photosynthesis”.