Practice problem
Find the equation of the line through the point (−6,10)(-6,10)(−6,10) and parallel to the line 2x−3y=−32x-3y=-32x−3y=−3.
y=23 x−6y=\frac{2}{3}\ x-6y=32 x−6
y=23 x+14y=\frac{2}{3}\ x+14y=32 x+14
y=32 x−6y=\frac{3}{2}\ x-6y=23 x−6
y=32 x+14y=\frac{3}{2}\ x+14y=23 x+14
Type a concept, like “slope” or “photosynthesis”.
