Practice problem
Which lines are perpendicular to the line y=13x+2y=\frac{1}{3}x+2y=31x+2?
y=3x+4y=3x+4y=3x+4
y=8−3xy=8-3xy=8−3x
3−y=1−3x3-y=1-3x3−y=1−3x
y=−3(x+5)y=-3(x+5)y=−3(x+5)
−13y=−(5−x)-\frac{1}{3}y=-(5-x)−31y=−(5−x)
y=−13x+2y=-\frac{1}{3}x+2y=−31x+2
Type a concept, like “slope” or “photosynthesis”.
