Practice problem
Find the line perpendicular to y=−13x−1y=-\frac{1}{3} x-1y=−31x−1 and containing the point (3,9)(3,9)(3,9).
y=8x+28y=8x+28y=8x+28
y=6−2xy=6-2xy=6−2x
y=4−3xy=4-3xy=4−3x
y=3xy=3xy=3x
Type a concept, like “slope” or “photosynthesis”.
