Practice problem
Simplify x−7x2−6x−7 ⋅x2−13x+42x+1\frac{x-7}{x^2-6x-7}\ \cdot\frac{x^2-13x+42}{x+1}x2−6x−7x−7 ⋅x+1x2−13x+42 when x2−6x−7≠0x^2-6x-7\ne 0x2−6x−7=0 and x+1≠0x+1\ne 0x+1=0.
(x−1)(x+9)(x+1)2\frac{(x-1)(x+9)}{(x+1)^2}(x+1)2(x−1)(x+9)
(x−8)(x−1)(x+1)2\frac{(x-8)(x-1)}{(x+1)^2}(x+1)2(x−8)(x−1)
(x−3)(x+2)(x+1)2\frac{(x-3)(x+2)}{(x+1)^2}(x+1)2(x−3)(x+2)
(x−6)(x−7)(x+1)2\frac{(x-6)(x-7)}{(x+1)^2}(x+1)2(x−6)(x−7)
Type a concept, like “slope” or “photosynthesis”.
