Simplify 2x2+6x−8x2−3x−28 ⋅2x2−6x−56x2−7x+6\frac{2x^2+6x-8}{x^2-3x-28}\ \cdot \frac{2x^2-6x-56}{x^2-7x+6} when x2−3x−28≠0x^2-3x-28\ne0 and x2−7x+6≠0x^2-7x+6\ne0.

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