Practice problem
Simplify: x3−14x2+48xx2−13x+40 ⋅x2−2x−15x2y−3xy−18y\frac{x^3-14x^2+48x}{x^2-13x+40}\ \cdot \frac{x^2-2x-15}{x^2y-3xy-18y}x2−13x+40x3−14x2+48x ⋅x2y−3xy−18yx2−2x−15 when (x2−13x+40)(x2y−3xy−18y)≠0(x^2-13x+40)(x^2y-3xy-18y)\ne 0(x2−13x+40)(x2y−3xy−18y)=0.
xy\frac{x}{y}yx
x−3y+6\frac{x-3}{y+6}y+6x−3
x+8y+8\frac{x+8}{y+8}y+8x+8
x2y2\frac{x^2}{y^2}y2x2
Type a concept, like “slope” or “photosynthesis”.
