The system {x≥0,y≥0,x≤0,y≤0}\{x \ge 0, y \ge 0, x \le 0, y \le 0\} has exactly 1 solution: (x,y)=(0,0).(x,y) = (0,0). Can you do better?

What is the fewest number of linear inequalities ax+by+c≥0ax+by+c \ge 0 (for real constants a,b,ca,b,c) you need to get a system of inequalities with exactly 1 solution?

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