Practice problem
=== If you have a rational number pq\frac{p}{q}qp where q≠0q\neq0q=0, then pq(a+b)=paq+pbq\frac{p}{q} (a+b)=\frac{pa}{q} +\frac{pb}{q}qp(a+b)=qpa+qpb.
True
False
Not enough information given.
Type a concept, like “slope” or “photosynthesis”.
