Find the minimum (lowest) real root of x3−26x−5=0x^3 - 26x - 5 = 0, rounded to the nearest hundredth.

Hint: Rewrite the equation as −x(5)2−5+(x3−x)=0-x(5)^2 -5 + (x^3 - x) = 0, and use the "quadratic formula" (or complete the square) in the variable 5.

Source: Razvan Gelca

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