Practice problem
Solve the following system of equations in matrix form. [42−1−132−413][xyz]=[147−5]\begin{bmatrix} 4 & 2 & -1 \\ -1 & 3 & 2 \\ -4 & 1 & 3 \end{bmatrix} \begin{bmatrix} x \\ y \\ z \end{bmatrix} = \begin{bmatrix} 14 \\ 7 \\ -5 \end{bmatrix}4−1−4231−123xyz=147−5
x=3x = 3x=3, y=−2y = -2y=−2, z=1z =1z=1
x=0x = 0x=0, y=5y = 5y=5, z=−4z = -4z=−4
x=5x = 5x=5, y=0y = 0y=0, z=6z = 6z=6
x=1x = 1x=1, y=4y = 4y=4, z=−2z = -2z=−2
x=2x = 2x=2, y=3y = 3y=3, z=0z = 0z=0
Type a concept, like “slope” or “photosynthesis”.