Practice problem
Assume 2x=3y2^x = 3^y2x=3y. Solve for yyy.
y=3x2y = \frac{3x}{2}y=23x
y=log3(x)y = \log_3(x)y=log3(x)
y=log2(3)⋅xy = \log_2(3) \cdot xy=log2(3)⋅x
y=log3(2)⋅xy = \log_3(2) \cdot xy=log3(2)⋅x
y=213xy = 2^{\frac{1}{3} x}y=231x
Type a concept, like “slope” or “photosynthesis”.