Practice problem
2∗8∗[1111]2*8*\begin{bmatrix}1&1\\1&1\end{bmatrix}2∗8∗[1111] is equal to...
2∗8∗[1111]2*8*\begin{bmatrix}1&1\\1&1\end{bmatrix}2∗8∗[1111]
16∗[1111]16*\begin{bmatrix}1&1\\1&1\end{bmatrix}16∗[1111]
[16161616]\begin{bmatrix}16&16\\16&16\end{bmatrix}[16161616]
8∗[2222]8*\begin{bmatrix}2&2\\2&2\end{bmatrix}8∗[2222]
2∗[4444]2*\begin{bmatrix}4&4\\4&4\end{bmatrix}2∗[4444]
Type a concept, like “slope” or “photosynthesis”.
