Practice problem
If you rationalize the denominator of the expression 3−53−20 \dfrac{3-\sqrt5}{3-\sqrt{20}}\;\;3−203−5 what does it look like after?
9+35−1029\dfrac{9+3\sqrt5-10}{29}299+35−10
9+35−10−11\dfrac{9+3\sqrt5-10}{-11}−119+35−10
9+35−10−20\dfrac{9+3\sqrt5-10}{-20}−209+35−10
9−35−10−11\dfrac{9-3\sqrt5-10}{-11}−119−35−10
Type a concept, like “slope” or “photosynthesis”.