Let aa, bb, cc, xx, yy, and zz be real numbers that satisfy the three equations 13x+by+cz=0ax+23y+cz=0ax+by+42z=0.\begin{align*} 13x + by + cz &= 0 \\ ax + 23y + cz &= 0 \\ ax + by + 42z &= 0. \end{align*}Suppose that a≠13a \ne 13 and x≠0x \ne 0. What is the value of 13a−13+23b−23+42c−42?\frac{13}{a - 13} + \frac{23}{b - 23} + \frac{42}{c - 42} ?

(Hint: The determinant of the matrix [13bca23cab42]\begin{bmatrix}13 & b& c \\ a& 23& c \\ a& b &42\end{bmatrix} is zero. Now try playing with row operations to get 13/(a−3)13/(a-3), etc. to pop up.)

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