If −1<x<1-1 < x < 1 and −1<y<1-1 < y < 1, define the "relativistic sum'' x⊕yx \oplus y to be x⊕y=x+y1+xy.x \oplus y = \frac{x + y}{1 + xy} . The operation ⊕\oplus is commutative and associative. Let vv be the number v=177−1177+1.v = \frac{\sqrt[7]{17} - 1}{\sqrt[7]{17} + 1} . What is the value of v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v⊕v?v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v \oplus v? (In this expression, ⊕\oplus appears 1313 times.)

(Hint: What does r−1r+1⊕s−1s+1\frac{r-1}{r+1} \oplus \frac{s-1}{s+1} simplify to?)

Source: Math Prize for Girls

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