Practice problem
Let f(x)=2x+8f(x) = 2x + 8f(x)=2x+8. What is f−1f^{-1}f−1?
f−1=x2−4f^{-1} = \frac{x}{2} - 4f−1=2x−4
f−1=x2−8f^{-1} = \frac{x}{2} - 8f−1=2x−8
f−1=−2x−8f^{-1} = -2x - 8f−1=−2x−8
f−1=2x−8f^{-1} = 2x - 8f−1=2x−8
f−1f^{-1}f−1 does not exist.
Type a concept, like “slope” or “photosynthesis”.