Practice problem
Solve this system of linear equations using the inverse. {ax+by=3b2c +dcx+dy=d(3ab+c2)ac\begin{cases}ax+by&=3\frac{b^2}{c}\ +d\\cx+dy&=\frac{d(3ab+c^2)}{ac}\end{cases}{ax+bycx+dy=3cb2 +d=acd(3ab+c2)
x=day=3bc\begin{align}x&=\frac{d}{a}\\y&=\frac{3b}{c}\end{align}xy=ad=c3b
x=bay=c2d\begin{align}x&=\frac{b}{a}\\y&=\frac{c}{2d}\end{align}xy=ab=2dc
x=a2y=2d3a\begin{align}x&=a^2\\y&=\frac{2d}{3a}\end{align}xy=a2=3a2d
x=cdy=ab\begin{align}x&=cd\\y&=ab\end{align}xy=cd=ab
Type a concept, like “slope” or “photosynthesis”.
