Practice problem
Solve the system of equations. {x−3y+2z=12x+2y+z= 43x+y+2z= 6\\\begin{cases}x-3y+2z&=12\\x+2y+z&=\ \ 4\\3x+y+2z&=\ \ 6\end{cases}⎩⎨⎧x−3y+2zx+2y+z3x+y+2z=12= 4= 6
x=−176y=−16z=436\begin{matrix}x=-\frac{17}6&y=-\frac{1}6&z=\frac{43}6\end{matrix}x=−617y=−61z=643
x=−72y=−12z=172\begin{matrix}x=-\frac{7}2&y=-\frac{1}2&z=\frac{17}2\end{matrix}x=−27y=−21z=217
x=−596y=56z=736\begin{matrix}x=-\frac{59}6&y=\frac{5}6&z=\frac{73}6\end{matrix}x=−659y=65z=673
x=−135y=−15z=7\begin{matrix}x=-\frac{13}{5}&y=-\frac{1}{5}&z=7\end{matrix}x=−513y=−51z=7
Type a concept, like “slope” or “photosynthesis”.
