Practice problem
Which of the following is equal to: ∑i=131(x+1)i\sum_{i=1}^3 \frac{1}{(x+1)^i}i=1∑3(x+1)i1
x2+3x+3x3+3x2+3x+1\frac{x^2 + 3x + 3}{x^3 + 3x^2 + 3x + 1}x3+3x2+3x+1x2+3x+3
x2+3x+2x3+3x2+3x+1\frac{x^2 + 3x + 2}{x^3 + 3x^2 + 3x + 1}x3+3x2+3x+1x2+3x+2
x2+3x+3x2+2x+1\frac{x^2 + 3x + 3}{x^2 + 2x + 1}x2+2x+1x2+3x+3
x2+3x+2x2+2x+1\frac{x^2 + 3x + 2}{x^2 + 2x + 1}x2+2x+1x2+3x+2
111
Type a concept, like “slope” or “photosynthesis”.