lim⁡n→∞(n2+3n−53n2−2n⋅12n3+2n2−7−n3−5n2−5n−4)=\lim_{n \to \infty} \left(\frac{n^2 + 3n - 5}{3n^2 - 2n} \cdot \frac{12n^3 + 2n^2 - 7}{-n^3 - 5n^2 - 5n - 4} \right) =
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