Practice problem
Let limx→32sin(x)=a\lim_{x \to 3} 2\sin(x) = alimx→32sin(x)=a and limx→1ex=b\lim_{x \to 1} e^x = blimx→1ex=b. What is limx→14sin(3x)+3ex\lim_{x \to 1} 4\sin(3x) + 3e^xlimx→14sin(3x)+3ex?
4a+3b4a + 3b4a+3b
2a+3b2a + 3b2a+3b
a+ba + ba+b
Cannot be determined from the given information.
Type a concept, like “slope” or “photosynthesis”.