Practice problem
Write the equation of the circle centered at (3,9)(3,9)(3,9) with radius 666.
(x−3)2+(y−9)2=36(x-3)^2+(y-9)^2=36(x−3)2+(y−9)2=36
(x−3)2+(y−9)2=6(x-3)^2+(y-9)^2=6(x−3)2+(y−9)2=6
∣x−3∣+∣y−9∣=6|x-3|+|y-9| = 6∣x−3∣+∣y−9∣=6
(x−32)+(y−92)=62(x-3^2)+(y-9^2) = 6^2(x−32)+(y−92)=62
(x2−3)+(y2−9)=6(x^2-3)+(y^2-9) = 6(x2−3)+(y2−9)=6
(x2−3)+(y2−9)=62(x^2-3)+(y^2-9) = 6^2(x2−3)+(y2−9)=62
Type a concept, like “slope” or “photosynthesis”.